c - why is my printf doing this? -

it seems such silly thing ask don't know why happening. it's 5am , i'm still doing but..

it should print -ca why when compile it, printing

- ca? 

instead of -ca, there isn't '\n' anywhere in sight. can guys think of logical explain it?

int main(int argc, char* argv[]){  int check = 0; char *thing = (char*)malloc(2 * sizeof(char));  strcpy(char, "ca");  code..     do{      more code...      if(condition== 1) {             more code....              if(check == 0) {                  printf("-");                 check++;             }       if (some conditon != null){         printf("%s\n",thing);     }while(condition)   return 0; 

}

you didn't allocate enough space string. every string has null terminator, 2-character string needs 3 bytes in array. strcpy() writing outside bounds of thing array when copies null byte, results in undefined behavior.

use

char *thing = malloc(3); 

you can use strdup(), makes copy of string in dynamic memory, automatically allocating enough space based on length of original string.

char *thing = strdup("ca");