java - Strange error in switch -

i created program taking criminal case , storing it, , added switch can access other stuff wish add in program. there seems error when choice executed. switch won't recognize choice, , instead repeats menu resides within loop. there's no error during compilation. here's coding...

import java.util.arraylist; import java.util.scanner;  public class criminalcase {         private string batput;     public string getbatput(){return batput;}       public criminalcase(string batput){         this.batput = batput;      }  private static class robin{    string batman(){ scanner s=new scanner (system.in); system.out.println(); system.out.println("enter name."); string a=s.nextline(); system.out.println("enter date of birth."); string b=s.nextline(); system.out.println("enter sex."); string c=s.nextline(); system.out.println("enter crime committed."); string d=s.nextline(); system.out.println("enter date of crime committed."); string e=s.nextline(); system.out.println("enter victim."); string f=s.nextline(); system.out.println(); string g=""+"\n"+""+"name:- "+a +"\ndob:- "+b +"\nsex:- "+c +"\ncrime committed:- "+d +"\ndate of crime committed:- "+e +"\nvictim:- "+f;  system.out.println(); return g;   } }        public static void main(string[] args) {           arraylist<criminalcase> cases = new arraylist<>();         boolean quit = false;              scanner s = new scanner(system.in);           robin j=new robin();           boolean exit=false; for(;!exit;){ system.out.println("for cases press 1.\nfor printing thank you, press 2.\nto exit, press 3."); int choice=s.nextint(); switch (choice){ case 1:{          while (!quit) {             system.out.println();             system.out.println("to view current cases enter v\nto add case enter a\nto quit enter q");             string input = s.nextline();              switch(input){                 case ("v"): {                     system.out.println("");                     system.out.println("the following cases exist:");                     system.out.println("\nname:- batman\ndob:- unknown\nsex:- male\ncrime committed:- tresspassing crime scene, fleeing scene of crime, carrying unlicensed vehicles ,   weapons.\ndate of crime committed:- 18/9/2015\nvictim:- none.");                     (criminalcase c : cases)                     system.out.println(c.getbatput());                     break;                 }                 case("a"):{                     string batput=j.batman();                      cases.add(new criminalcase(batput));                     break;                 }                 case("q"):{                     quit = true;                   }              }         } break;     } case 2:system.out.println("thank you.");  break;  case 3:exit=true;         }      }   } 

}

without testing guess bug in piece of code:

int choice=s.nextint(); switch (choice) { case 1:{      while (!quit) {         system.out.println();         system.out.println("to view current cases enter v\nto add case enter a\nto quit enter q");         string input = s.nextline(); 

you reading integer nextint() method, , then, should call nextline() follows

int choice=s.nextint(); s.nextline() switch (choice) { .... 

look @ question understand behavior:

scanner skipping nextline() after using next(), nextint() or other nextfoo() methods

edit (my personal advice):

i reading single integer in 1 line follows:

int choice = integer.parseint(s.nextline()); 

try implement version