eclipse - Open Android App or URL -


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i have started final year android project , wondering when user presses button how open, example, facebook app , if user not have facebook app installed redirected m.facebook.com in browser?

thanks in advanced.

you can use try/catch handle it. if facebook app installed, fb://page/123 link open in app. else, catch code run.

        @override         public void onclick(view v) {             try {                 startactivity(new intent(intent.action_view, uri                         .parse("fb://page/12345"))); //12345 facebook page number             } catch (exception e) {                 //open link in browser                 startactivity(new intent(intent.action_view, uri                         .parse("http://m.facebook.com/etc")));             }         } 

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