i have static list of values in jsonarray. here example array:
jsonarray json = new jsonarray() json = ["b", "e", "c", "z", "a", "x", "f", "h"] i need sort json array in custom way. need put "e" first, "f" second, , sort rest alphabetical order.
i want end result this:
json = ["e", "f", "a", "b", "c", "h", x", "z"] groovy has basic sort functionality can sort alphabetically or reverse alphabetically using:
json.sort() or
json.reverse() i'm looking easy way custom sort.
you can use closures if define own sort method, you're asking array splitting little normal sorting.
json.findall{it = 'e'} + json.findall{it = 'f'} + json.findall{!(it in ['e', 'f'])}.sort() if you're worried efficiency of looping through json 3 times can iterate through json once, adding different arrays go.
the below example little fancier. inject method iterate on collection, passing value between each iteration (in our case list of 3 lists. first list hold our e's, second our f's, , 3rd else. after sorting our catchall list use .flatten() transform 3 lists 1 list.
list organizedlist = json.inject([[],[],[]]) {list<list> result, string jsonvalue -> select(jsonvalue) { case 'e': result.get(0).add(jsonvalue) // have added 'e' symmetry break; case 'f': result.get(1).add(jsonvalue) break; default: result.get(2).add(jsonvalue) } return result // gets passed each iteration on json } organizedlist.get(2).sort() // sort on list modifies original list organizedlist.flatten() it's possible using sort closure define own sorting; can see, doesn't flow quite easily.
json.sort {string a, string b -> if (a = b) return 0 // efficiency's sake def letterfirst = {string priority -> // closure sort against hardcoded value if (a = priority) return 1 if (b = priority) return -1 return 0 } def toreturn = letterfirst('e') if (!toreturn) toreturn = letterfirst('f') // groovy evaluates 0 false if (!toreturn) toreturn = <=> b return toreturn } 
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